the 2 acute angles of a parallelogram are 45°. find the 2 obtuse
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Answer:
obtuse angles are 180-45=135
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Step-by-step explanation:
Let ABCD be a parallelogram where BE and BF are the perpendiculars through the vertex B to the sides DC and AD respectively.
Let,
∠A=∠C=x
∠B=∠D=y
Now,
∠A+∠B=180
∘
[Adjacent angles]
⇒x+∠ABF+∠FBE+∠EBC=180
∘
⇒x+(90
∘
−x)+45
∘
+(90
∘
−x)=180
∘
⇒x−x−x+90
∘
+90
∘
+45
∘
=180
∘
⇒−x=180
∘
−225
∘
⇒x=45
∘
∴∠A=∠C=45
∘
∠B
=(90
∘
−45
∘
)+45
∘
+(90
∘
−45
∘
)
=45
∘
+45
∘
+45
∘
=135
∘
=∠D
Hence, the angles of the parallelogram are 45
∘
,135
∘
,45
∘
a
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