Math, asked by sakthi59, 10 months ago

the 2 digit no is such that the productof its digits is 21 .If 36 is subtracted from the nos ,the digitsvare interchanged . find the nos. x:5(3z-5/x-3)-33(x-3/3x+5)=-52​

Answers

Answered by Anonymous
0

Answer:

Let the unit digit of the number be x

and the tens digit of the number be y.

Thus,

The required number will be (10y + x)

Also,

It is given that, the product of the digits is 21.

=> x•y = 21 ----------(1)

Now,

New number formed after interchanging the digits will be (10x + y).

As per the question,

If 36 is subtracted from the required number then the digits are interchanged.

ie;

=> (10y + x) - 36 = 10x + y

=> 10x + y - 10y - x + 36 = 0

=> 9x - 9y + 36 = 0

=> 9(x - y + 4) = 0

=> x - y + 4 = 0

=> y = x + 4 --------(2)

Now,

Putting y = x + 4 in eq-(1) ,we get;

=> x•y = 21

=> x(x + 4) = 21

=> x^2 + 4x = 21

=> x^2 + 4x - 21 = 0

=> x^2 + 7x - 3x - 21 = 0

=> x(x + 7) - 3(x + 7) = 0

=> (x + 7)(x - 3) = 0

=> x = -7 , 3

Here, x = -7 will be rejected (as digit of a number is never negative) .

Thus, the appropriate value of x is 3.

{ Note; In mathematics, there are just ten digits , ie; 0,1,2,3,4,5,6,7,8,9. }

Now,

Putting x = 3 in eq-(2) , we get;

=> y = x + 4

=> y = 3 + 4

=> y = 7

Thus,

The unit digit of required number is 3

and the tens digit is 7.

Hence, the required number is 73.

Trick to solve;

Here , in the first statement of the question ,it is given that, the product of digits of a two digits number is 21.

21 can be written as 3×7 or 7×3.

Thus,

If unit digit is 3, then tens digit must be 7.

And ,if unit digit is 7 , then tens digit must be 3.

Thus, as per first statement of the question, two numbers can be taken under consideration, ie; 73 and 37.

Now, in the second statement of the question it is given that , if 36 is subtracted from the number, the digits are interchanged.

So, let's check, which number (37 or 73) fulfill the second condition.

When 36 is subtracted from 37;

37 - 36 = 1 (condition not fulfilled)

When 36 is subtracted from 73;

73 - 36 = 37 ( condition fulfilled)

Thus, required number is 73.

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