Question

The 2 digit number which becomes (5/6)th of itself when its digits are reversed. The difference in the digits of the number

being 1, then the two digits number is ​

Answer 1

Step-by-step explanation:

Let the number be =10a+b

Let the number be =10a+b10b+a=

Let the number be =10a+b10b+a= 6

Let the number be =10a+b10b+a= 65

Let the number be =10a+b10b+a= 65

Let the number be =10a+b10b+a= 65 (10a+b),

Let the number be =10a+b10b+a= 65 (10a+b),anda−1=b,

Let the number be =10a+b10b+a= 65 (10a+b),anda−1=b,5(10a+a−1)=6(10a−10+a)

Let the number be =10a+b10b+a= 65 (10a+b),anda−1=b,5(10a+a−1)=6(10a−10+a)55a−5=66a−60,

Let the number be =10a+b10b+a= 65 (10a+b),anda−1=b,5(10a+a−1)=6(10a−10+a)55a−5=66a−60,11a=55,

Let the number be =10a+b10b+a= 65 (10a+b),anda−1=b,5(10a+a−1)=6(10a−10+a)55a−5=66a−60,11a=55,a=5,b=4