Question

the
2. For what value of p,6 is a zero of
polynomial x² (2p+1) x+6​

Answer 1

Answer:

p=-4

x^2+(2p+1)x+6=0

x^2+2px+x+6=0---------if x=6

then

(6)^2+2p6+6+6=0

36+12p+12=0

48+12p=0

p=-48/12

p=-4