Question

the 2 parallel sides of trapezium 19.8 cm and 10.2cm if the area of the trapezium is 180 find distance between the parallel side​

Answer 1

Here is your answer ........

Answer 2

Given :

• ${B}_{1} \longrightarrow 19.8 cm$
• ${B}_{2} \longrightarrow 10.2 cm$
• $Area\:of\:Trapezium \longrightarrow 180\:{cm}^{2}$

To find :

• Height = h

Area of Trapezium :

• $\boxed{\mathtt{\frac{1}{2} \times \frac{{b}_{1}+{b}_{2}}{2} \times h}}$

$\mathtt{180\:{cm}^{2} = \frac{1}{2} \times \frac{19.8\:cm+10.2\:cm}{2} \times h }$

$\mathtt{360\:{cm}^{2} = 15\:cm \times h }$

$\mathtt{\frac{360\:{cm}^{2}}{30\:cm} = h }$

$\mathtt{12\:cm = h }$

Hence, the distance between parallel sides or height of parallelogram is 12 cm .