The 20 th term of an AP is 100 more than its 10th term. What is the common difference ( d) of the AP?
a.12
b.10
c.9
d.8
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10
=a+9d=100
t
20
=a+19d=400
a+19d−a−9d=400−100
10d=300
d=
10
300
=30
Substituting d=30 in a+9d=100 we get
a+9×30=100
⇒a=100−270=−170
∴t
100
=a+99d=−170+99×30=−170+2970=
=a+9d=100
t
20
=a+19d=400
a+19d−a−9d=400−100
10d=300
d=
10
300
=30
Substituting d=30 in a+9d=100 we get
a+9×30=100
⇒a=100−270=−170
∴t
100
=a+99d=−170+99×30=−170+2970=
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