Math, asked by jgxkgdkgdigd, 1 year ago

the 2006 digit in the sequence 12345678910111213 is

Answers

Answered by VEDULAKRISHNACHAITAN
20

Answer: 0


Step-by-step explanation:

All the natural numbers starting from 1 are enlisted:

So number of 1 digit numbers = 9

number of 2 digit numbers = 90(to calculate number of digits we need to multiply by 2)

number of 3 digit numbers starting from 100 till 699 = 600(to calculate number of digits we need to multiply by 3)

So, starting from 1 to 699, total number of digits will be

9 + 2*90 + 3*600 = 1989.

If we also add 700-704 we get total 1989 + 15 = 2004 digits enlisted.

Now the 2006 digit in the sequence is clearly evident that would be the second digit of 705 which is 0.


Similar questions