the 20th and 30th terms of an AP are 201 and 301 respectively. Find c.d
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Common difference(d) = 10
Step-by-step explanation:
★ Given that,
➡ 20th term of an AP : 201
- a20 = 201
➡ 30th term of an AP : 301
- a30 = 301
★ To find,
- Common difference(d).
★ Let,
◼ a20 : a + 19d = 201 ..... (1)
◼ a30 : a + 29d = 301 ..... (2)
- Subtract equations (1) & (2)
a + 19d = 201
a + 29d = 301
- - -
_____________
- 10d = - 100
_____________
➠ - 10d = - 100
➠ 10d = 100
➠ d = 100/10
➠ d = 10
Now substitute the value of d in equation (1).
➠ a + 19(10) = 201
➠ a + 190 = 201
➠ a = 201 - 190
➠ a = 11
★ Verification,
Substitute the values of a & d in (1), to get LHS = RHS.
LHS = a + 19d
➠ 11 + 19(10)
➠ 11 + 190
➠ 201
Since, LHS = RHS.
Hence, it was verified.
∴ Common difference (d) = 10
★ More info :
Formula related to Arithmetic Progression :
☯ an = a + (n - 1)d
☯ Sn = n/2[ 2a + (n - 1)d ]
Where,
- a = first term of AP.
- n = number of terms of AP.
- d = common difference(d) of AP.
- an = nth term of AP.
- Sn = sum of nth terms of AP.
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