The 20th term of an AP whose 3rd term is 7 and the 7th term exceeds three times the third term by 2. Also find its nth term
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let the first term of ap =a
let the common difference=d
given:
1.3rd term = 7
a+2d=7. ----(1)
2. 7th term exceeds the third term by two
a+6d= a+2d+2
4d = 2
d= 1/2
put the value of d in equation 1
a+2(1/2)= 7
a=6
20 th term = a+19d
6+19(1/2)= 6+9.5= 15.5
nth term = a+(n-1)d= 6+(n-1)1/2
= (11+n)/2
hope it helps you
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