Question

The 20th term of the series 64-16+4-1 is options a-1/2^16 b.1/2^16 c.1/4^16 d.-1/4^16​

Answer 1

Answer:

I think the answer is A

I think

Answer 2

Answer

-1/4^16. B

Step-by-step explanation:

G.P=

${ar}^{n - 1}$

r=

$\frac{ - 16}{64}$

$\frac{ - 1}{4}$

=

$64( { \frac{ - 1}{4} })^{20 - 1 }$

$64( { \frac{1}{4} })^{19}$

${4}^{3} ( \frac{1}{ {4}^{19} } )$

$( \frac{ - 1}{ {4}^{19 - 3} } )$

=

$\frac{ - 1}{ {4}^{16} }$