The 21 term of the a.p.whose first two terms are -3and4 is
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4
solution
Here is your answer...
given first A.P = a¹=-3
and a²= 4
now common difference D= a²-a¹= 4--3=4+3=7
according to question,
find 21 St term N= 21
T21= A+(n-1)×D
=-3+(21-1)×7
= -3+140
T21= 137
hope it help you
pls follow tannuranna 59 and as 8980966 in my following
Answered by
0
Step-by-step explanation:
An=a+(n-1)d
Here,
An is the term we need
a is the first term
n is the required term
d is common difference
we need to find,
21 st term
Here
a =-3
d =7
n =21
so, using formula
A21 = -3+(21-1)7
=-3+(20)7
= -3+140
= 137
Therefore the 21 st term of the A.P is 137
Hope this helps you!!!!!!
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