Math, asked by palashu018, 9 months ago

The 21 term of the a.p.whose first two terms are -3and4 is

Answers

Answered by handsomeram16645
4

solution

Here is your answer...

given first A.P = a¹=-3

and a²= 4

now common difference D= a²-a¹= 4--3=4+3=7

according to question,

find 21 St term N= 21

T21= A+(n-1)×D

=-3+(21-1)×7

= -3+140

T21= 137

hope it help you

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Answered by Nalindevu
0

Step-by-step explanation:

An=a+(n-1)d

Here,

An is the term we need

a is the first term

n is the required term

d is common difference

we need to find,

21 st term

Here

a =-3

d =7

n =21

so, using formula

A21 = -3+(21-1)7

=-3+(20)7

= -3+140

= 137

Therefore the 21 st term of the A.P is 137

Hope this helps you!!!!!!

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