the 21st term of A.P.3,8,13........is
nab92:
Biswajit hoi ne baru...
Answers
Answered by
8
hey mate here is your answer
AP=3,8,13,..........
so a=first term=3
and d= common difference=a2-a1
=8-3
=5
so by using an=a + ( n-1 )d
a21=3+(21-1)5
a21=3+20×5
a21=3+100
a21=103
hope it will help you
mark me brainliest ✌✌✌✌
AP=3,8,13,..........
so a=first term=3
and d= common difference=a2-a1
=8-3
=5
so by using an=a + ( n-1 )d
a21=3+(21-1)5
a21=3+20×5
a21=3+100
a21=103
hope it will help you
mark me brainliest ✌✌✌✌
Answered by
2
Given sequence : 3 , 8 , 13 ....
Now,
First term = a = 3
Second term = a + d = 8
Common difference = ( a + d ) - a = 8 - 3 = 5
We know ( formula) ,
zth term = a + ( z - 1 )d , where a is the first term, d is the common difference and z is the Number of terms.
Now,
21st term = a + ( 21 - 1 )d
= > 3 + ( 21 - 1 )5
= > 3 + ( 20 x 5 )
= > 3 + 100
= > 103
Therefore, 21st term of the AP is 103
Now,
First term = a = 3
Second term = a + d = 8
Common difference = ( a + d ) - a = 8 - 3 = 5
We know ( formula) ,
zth term = a + ( z - 1 )d , where a is the first term, d is the common difference and z is the Number of terms.
Now,
21st term = a + ( 21 - 1 )d
= > 3 + ( 21 - 1 )5
= > 3 + ( 20 x 5 )
= > 3 + 100
= > 103
Therefore, 21st term of the AP is 103
Similar questions