The 21st term of an AP whose first two term are -3 and 4 is?
Answers
Answered by
22
a= -3
d=7
n=21
An=a+(n-1)d
An= -3+(21-1)7
= -3+(20)7
= -3+140
=137
it is easy & simple way
Hope it will help u
d=7
n=21
An=a+(n-1)d
An= -3+(21-1)7
= -3+(20)7
= -3+140
=137
it is easy & simple way
Hope it will help u
Answered by
3
here, a=-3
d=7
n=21
an=a+(n-1)*d
-3+(21-1)*7
-3+20*7
-3+140
137
d=7
n=21
an=a+(n-1)*d
-3+(21-1)*7
-3+20*7
-3+140
137
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