the 21st term of an AP whose first two terms are -3and 4 is
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6
Answer:
137
Step-by-step explanation:
a=-3
a2=4
4=a+(n-1)d
4=-3+(n-1)7
n=2
a21=a+(n-1)d
a21=-3+20x7
a21=137
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1
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