Question

The 21st term of the Arithmetic Progression 5, 7, 9, 11

Answer 1

Answer:This is A.P series

Where first term (a) = 5

Common difference = 7–5=2

Number of term =21

Last term = a+(n-1)d

Last term = 5+(21–1)2= 5+20*2=45

Answer 2

Answer:

45

Step-by-step explanation:

Given

A. P-5, 7,9,11,....

a=5 , d= 7-5=2, n=21

To find :

21st term = ?

SOLUTION

t(21) =?

t(n) = a+(n-1) d

t(21)= 5+(21-1)2

t(21)=5+(20)2

t(21)=5+40

t(21)=45

Ans:45