Question

the 23rd term of an arithematic sequence is 32 and the 35th term is 104 find the first term​

Answer 1

Answer:

first term of the series is -100

Step-by-step explanation:

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Answer 2

Step-by-step explanation:

Let's try to do this!

Given,

t23=32

a+22d=32

a=32-22d..............1)

t35=104

a+34d=104

a=104-34d..............2)

Equating both equations, we get,

a=a

32-22d =104-34d

34d-22d=104-32

12d=72

d=72/12

d= 6

Now, putting the value of d in eq2) we get,,

a= 104-34×6

a=104-204

a=-100

Note:- I don't whether it is correct answer or not...

but the process and language are absolutely correct...

if you think, it's good e explanation you can mark me ,if you don't then that's your choice..