The 24th term of an A. P is twice it's 10th term. Show that it's 72nd term is 4times it's 15th term
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t24=2t10
a+23d=2a+18d
23d-18d=2a-a
a=5d
t72= a+71d=5d+71d=76d
t15=a+14d=5d+14d=19d
76d=4(19d)
t72=4×t15
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