The 24th term of an A.P. is twice its 10th term, find its 30th term
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Heya !!
A.T.Q.
(a+23d) = 2(a+9d)
=> a + 23d = 2a + 18d
=> 23d - 18d = 2a -a
=> 5d = a
30th term i.e.,
= a+29d
Substituting a=5d
= 5d + 29d
= 34d
A.T.Q.
(a+23d) = 2(a+9d)
=> a + 23d = 2a + 18d
=> 23d - 18d = 2a -a
=> 5d = a
30th term i.e.,
= a+29d
Substituting a=5d
= 5d + 29d
= 34d
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