Question

The 24th term of an A.P. is twice its 10th term. Show that its 72nd term is 4 times its 15th term. ​

Answer 1

Answer:

The 24th term of an A.P. is twice its 10th term. Show that its 72nd term is 4 times its 15th term. = ​4 is your answer

Step-by-step explanation:

Let a= first term of A.P.,

d= common difference

n  term, a  24  = 2a  10

​⇒ a + 23d = 2(a + 9d)

⇒ a + 23d = 2a + 18d

⇒ a = 5d

Now, $\frac{a72}{a15}$ = $\frac{a + 71d}{a+14d}$

⇒ $\frac{76d}{19d}$

⇒ 4

Hope It Helps You