The 24th term of an A.P. is twice its 8th term. If the 11th term of the A.P. is 43, then find its
nth term.
Answers
Answered by
1
Answer:
387/19 + (n-1)(43/19)
Step-by-step explanation:
Let the first term be a and common difference be d.
Hence, 24th term = a + (24-1)d = a + 23d
and, 8th term = a + (8-1)d = a + 7d
A.T.P.
=)a + 23d = 2(a + 7d)
=)a + 23d = 2a + 14d
=)a = 9d........(i)
Now, 11th term = 43
=)a + (11-1)d = 43
=)a + 10d = 43
=)9d + 10d = 43 [from (i)]
=)d = 43/19
Thus, a = 9d = 9(43/19) = 387/19
now, nth term= a + (n-1)d
= 387/19 + (n-1)(43/19)
Answered by
0
Answer:
i think your given data will wrong.... ..
Attachments:
![](https://hi-static.z-dn.net/files/de1/a01e75842476818401a4d42fb69a545e.jpg)
Similar questions