Math, asked by sahajnitsingh951, 10 months ago



The 24th term of an A.P. is twice its 8th term. If the 11th term of the A.P. is 43, then find its
nth term.​

Answers

Answered by acecloud
1

Answer:

387/19 + (n-1)(43/19)

Step-by-step explanation:

Let the first term be a and common difference be d.

Hence, 24th term = a + (24-1)d = a + 23d

and, 8th term = a + (8-1)d = a + 7d

A.T.P.

=)a + 23d = 2(a + 7d)

=)a + 23d = 2a + 14d

=)a = 9d........(i)

Now, 11th term = 43

=)a + (11-1)d = 43

=)a + 10d = 43

=)9d + 10d = 43 [from (i)]

=)d = 43/19

Thus, a = 9d = 9(43/19) = 387/19

now, nth term= a + (n-1)d

= 387/19 + (n-1)(43/19)

Answered by gauravraj51501
0

Answer:

i think your given data will wrong.... ..

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