Math, asked by sahajnitsingh951, 6 months ago



The 24th term of an A.P. is twice its 8th term. If the 11th term of the A.P. is 43, then find its
nth term.​

Answers

Answered by acecloud
1

Answer:

387/19 + (n-1)(43/19)

Step-by-step explanation:

Let the first term be a and common difference be d.

Hence, 24th term = a + (24-1)d = a + 23d

and, 8th term = a + (8-1)d = a + 7d

A.T.P.

=)a + 23d = 2(a + 7d)

=)a + 23d = 2a + 14d

=)a = 9d........(i)

Now, 11th term = 43

=)a + (11-1)d = 43

=)a + 10d = 43

=)9d + 10d = 43 [from (i)]

=)d = 43/19

Thus, a = 9d = 9(43/19) = 387/19

now, nth term= a + (n-1)d

= 387/19 + (n-1)(43/19)

Answered by gauravraj51501
0

Answer:

i think your given data will wrong.... ..

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