The 24th term of an AP 15 twice its 10th term. Show that its 72nd
term, is 4 times its 15th term.
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Answer:
a+23d=2(a+9d)
a+23d=2a+18d
5d=a. ----eq.1.
72nd term-
a+71d
5d+71d (by using eq.1)
76d.
15th term-
a+14d
5d+14d (by using eq.1)
19d.
therefore,
76d=4×19d
76d=76d
proved.
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