Question

The 24th term of an ap is twice the 10th term show that its 22nd term is 4 times its 15th term

Answer 1

Answer:

let the nth term   a +[n-1]d

Step-by-step explanation:

The 24th term of an ap is twice the 10th term

a+23d    = 2 [a+9d]

a+23d =2a+18d

23d-18d = 2a-a

  a = 5d

now   22nd  term   = a +21d =5d +21d = 26 d  

    15 th term  = a + 14 d = 5d +14d = 19 d    

i think your questio is wrong       it may be  

 The 24th term of an ap is twice the 10th term show that its 32nd term is 4 times its 5th term

now   32nd term   = a +31d =5d +31d = 36 d  

          5 th term  = a + 4 d = 5d +4d = 9 d    

now see     32 nd term  =  4 times 5 th term