Question

The 25 th term of an



a.P exceeds its 9 th term by 16 find its common difference

Answer 1

Answer:

1

Step-by-step explanation:

25th term=a+24d                                 [aₓ=a+(x-1)d]

16th term=a+15d

a₂₅=₁₆+9

a+24d=a+15d+9

9d=9

d=1

So, common difference =1

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Answer 2

Answer:

To find: Common Difference, d

nth term of an AP is given by,an = a + (n - 1) d

where,a is the first term, n is the number of terms in an AP and d is the common differenceTenth and seventeenth terms of this AP can be given as follows:

a10 = a + 9d

a17 = a + 16d

It is give that 17th term is 7 more than the tenth term, So

Subtracting 10th term from 17th term, we get;

a + 16d – a – 9d = 7

7d = 7

d = 1

Hence common difference of the A.P is 1

Step-by-step explanation:

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