Math, asked by rishikathakkar62222, 5 months ago

The 26th, 11th and the last term of an ap are 0,3 and respectively. find the common difference and the number of term plz don't give wrong answer ​

Answers

Answered by Anonymous
4

Answer:

Let a,d and n be the first term,common difference and number of terms of an AP respectively.

Now,

a

26

=a+25d=0 ...(1)

a

11

=a+10d=3 ...(2)

on doing (1)-(2) , we get

15d=−3

⇒d=

5

−1

On substituting the value of d in (1), we get

a+25×

5

−1

=0

⇒a=5

Again, a

n

=a+(n−1)d=

5

−1

On substituting the values of a and d, we get

5+(n−1)×

5

−1

=

5

−1

⇒(n−1)×

5

−1

=

5

−1

−5=

5

−26

⇒(n−1)=26

⇒n=27

Therefore,

d=

5

−1

,n=27

Answered by rajpoot22
3

Answer:

ANSWER

Let a,d and n be the first term,common difference and number of terms of an AP respectively.

Now,

a

26

=a+25d=0 ...(1)

a

11

=a+10d=3 ...(2)

on doing (1)-(2) , we get

15d=−3

⇒d=

5

−1

On substituting the value of d in (1), we get

a+25×

5

−1

=0

⇒a=5

Again, a

n

=a+(n−1)d=

5

−1

On substituting the values of a and d, we get

5+(n−1)×

5

−1

=

5

−1

⇒(n−1)×

5

−1

=

5

−1

−5=

5

−26

⇒(n−1)=26

⇒n=27

Therefore,

d=

5

−1

,n=27

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