the 26th,11th and the last term of an ap are 03 and - 1/5 respectively. Find the commom difference and the number of terms
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The 26th 11th and the last term of AP are 0 3 minus 1 by 5 respectively find the common difference and the number of terms - 3066441. ... -1/5 =( 25 + 1)/5 -1/5n
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a + 25 d = 0 ____ 1
a + 10 d = 3 ____2
an = -1/5 ____3
a + 25 d = 0
- a + 10 d = 3
_________________
0 + 15 d = -3
d = -1/5
a26 = a + 25d
0 = a + 25 (-1/5)
0 = a + -5
a = 5
eq 3
-1/5 = 5 + (n - 1) -1/5
-1/5 = 5 + 1/5n +1/5
-1/5 =( 25 + 1)/5 -1/5n
1/5n = (26 + 1)/5
1/5 n = 27/5
n = 27
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