Question

The 26th 11th and the last term of AP are 0 3 minus 1 by 5 respectively find the common difference and the number of terms

Answer 1

a + 25 d = 0 ____ 1
a + 10 d = 3 ____2
an = -1/5 ____3


         a + 25 d = 0
-        a + 10 d =  3
_________________
         0 + 15 d = -3
                    d = -1/5
a26 = a + 25d

0 = a + 25 (-1/5)
0 = a + -5
a = 5

eq 3

-1/5 = 5 + (n - 1) -1/5

-1/5 = 5 + 1/5n +1/5

-1/5 =( 25 + 1)/5 -1/5n

1/5n = (26 + 1)/5

1/5 n = 27/5

n = 27

Answer 2

Answer:

Step-by-step explanation:

a + 25 d = 0 ____ 1

a + 10 d = 3 ____2

an = -1/5 ____3

         a + 25 d = 0

-        a + 10 d =  3

_________________

         0 + 15 d = -3

                    d = -1/5

a26 = a + 25d

0 = a + 25 (-1/5)

0 = a + -5

a = 5

eq 3

-1/5 = 5 + (n - 1) -1/5

-1/5 = 5 + 1/5n +1/5

-1/5 =( 25 + 1)/5 -1/5n

1/5n = (26 + 1)/5

1/5 n = 27/5

n = 27