the 2nd ,3rd and last trem of and a.p are 7,3/4,2/1 and 6 1/2 recpectiely find the first trem and numbar of trem
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T2 = 7
T3 = 3/4
T4 = 2
Tn = 61/2
common difference, d = T3 - T2 = (-25/4)
T2 = a + (n - 1)d
7 = a + (-25/4)
a = 53/4
numbers of terms, n= ?
Tn = a + (n-1) d
61/2 = 53/4 + (n-1) (-25/4)
69/4 = [-25n/4 + 25/4 ]
11 = -25/4(n)
n = (-44/25)
HOPE IT HELPS YOU
T3 = 3/4
T4 = 2
Tn = 61/2
common difference, d = T3 - T2 = (-25/4)
T2 = a + (n - 1)d
7 = a + (-25/4)
a = 53/4
numbers of terms, n= ?
Tn = a + (n-1) d
61/2 = 53/4 + (n-1) (-25/4)
69/4 = [-25n/4 + 25/4 ]
11 = -25/4(n)
n = (-44/25)
HOPE IT HELPS YOU
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