The 2nd and the 5th term of an A.P. is - 4 and 8 respectively. Find the 3
rd term of an A.P.
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a2= -4
a5 = 8
i.e a+1d = -4____1
a+4d = +8 ____2
-. -. -
_____________
-3d = -4
Therefore , d= 4/3.....
Thus , from eqn 1
a+4/3 =-4
a = -4-4/3
a= -5.3
Therefore , value of A3 will be
A3=a+2d
-5.3 +2(4/3)
=3.3 ...
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