The 3/4th part of a conical vessel of internal radius 5 cm and height 24 cm is full of water. The water is emptied into a cylindrical vessel with internal radius 10 cm. Find the height of water in cylindrical vessel.
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Answer:
volume of cone ×3/4 = ammount of water in cone
volume of cone = 1/3πr²h
(1/3)×π×5²×24=π×8×25
volume of cone =200πcm²
ammount of water = (3/4)×(1/3)πr²h
=πr²h/4
200πcm²/4
50πcm²
water is emptied in cylindrical vessel,
ammount of water in cylinder=50πcm²
volume of water covered in cylinder=πr²h
50πcm²=π(10)²h. (π cut with π)
50/(10)²=h
50/100=h
1/2cm=h
0.5cm=h of water in cylinder.
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