Question

The 3/4th part of the conical vessel of internal radius of 5 cm and height 24cm is full of water .the water is empitical into a cylindrical vessel with internal radius 10 cm. find the height of water on cylindrical vessel.




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Answer 1

Step-by-step explanation:

Volume of water in the conical vessel will be equal to the volume of water in the cylindrical vessel.

Volume of a Cylinder of Radius "R" and height "h" =πR

2

h

Volume of a cone =

3

1

πr

2

h, where r is the radius of the base of the cone and h is the height.

Hence,

7

22

×10×10×h=

3

1

×

7

22

×5

2

×24

⇒h=2 cm

Hence, height of water in the cylindrical vessel is 2 cm.

Answer 2

Step-by-step explanation:

HEY MATE .....

$height \: of \: conical \: vessel \: \\ \\ = 24 |cm| \\ \\ \\ radius \: of \: conical \: vessel \: \\ \\ = 5 |cm| \\ \\ \\ the \: volume \: of \: water \: \\ \\ = \frac{3}{4} \times volume \: of \: the \: conical \: vessel \\ \\ \implies \: \frac{3}{4} \times \frac{1}{3} \pi {r}^{2} h \\ \\ \implies \: \frac{3}{4} \times \frac{1}{3} \pi \times 25 \times 24 \\ \\ \implies \: 150\pi \\ \\ radius \: of \: cylindrical \: vessel \\ \\ = 10cm \\ \\ volume \: of \: cylindrical \: vessel \\ \\ = volume \: of \: water \: \\ \\ \pi( {10)}^{2} h = 150\pi \\ \\ \implies \: h = \frac{150\pi}{100\pi} \\ \\ h = 1.5 |cm| \\ \\ \\ thus \: the \: h \: of \: cylindrical \: vessel \: \\ \\ = 1.5 |cm|$

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