the 3 cubes of silver edges 3 cm,4cm,5cm are emlted and recast into a single cube find the cost of the coating the surface new cube with gold at rate of rs3.50 per sq.cm
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Answered by
1
Answer:
Step-by-step explanation:
volume of first cube= 3×3×3
=27
Volume of 2nd cube=4×4×4
=64
Volume of 3rd cube=5×5×5
=125
Sum= 27+64+125
=216
cube root of 216 = 6
Total cost = 6×3.50
=21.
Therefore, 21Rs.
kabhsai14:
Mark it brainliest please
Answered by
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S1= 3cm
S2= 4cm
S3=5cm
V of cube : S³
V1= 3³= 27cm³
V3= 4³= 64cm³
V3= 5³= 125cm³
TOTAL:- 216cm³
V4= 216 cm³
S4³= 216 cm³
S4= ³√126 = 6cm
TSA of a cube = 6S²
TSA = 6×36
= 216cm²
Cost of coating = 216×3•5 cm
= rs. 756
I hope this will help you please mark my answer as brainliest answer.
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