Question

the
3. In quadrilateral PORS, PO || SR and PS 1 PO. Also, PO) = 8 cm and SR=QR = 5 cm. Find the area of​

Answer 1

Step-by-step explanation:

 

ANSWER

 Given : ∠QPS=90 ∠ SQR=90

PQ=12cm , PS=9cm , QR=8cm and SR=17cm 

By Pythagoras theorem in ΔSPQ we get :

⇒SP2+PQ2=SQ2

⇒92+122=SQ2

⇒81+144=SQ2

⇒SQ2=22

⇒SQ=225

⇒SQ=15cm

Area of the parallelogram = Area of triangle SPQ + area of triangle SQR.

⇒ Area of Triangle SPQ = 21×base×height 

⇒21×PQ×SP

⇒21×12×9

⇒ Area of triangle SPQ = 54cm2 

⇒ Area of Triangle SQR = 1/2×base×height 

⇒1/2×QR×SQ

⇒21×8×15⇒ Area of triangle SPQ = 60cm2 

Total area = area of triangle SPQ + area of trinagle SQR 

⇒54+60=114cm2

Area of quadrilateral PQRS is 114cm2