Question

the 3 numbers whose average is 70, the first is 1/9 times the sum of other 2. The first number is​

Answer 1

Answer:

let the three no.s be a,b and c

a+b+c/3=70

a+b+c=210(eq1)

according to the question the first no. i.e,a=1/9(b+c)

substituting a value in eq1 we get

1/9(c+b)+b+c=210

taking LCM we get

b+c+9b+9c=210*9

10b+10c=210*9

10(b+c)=210*9

b+c=210*9/10

b+c=21*9

so as a=1/9(b+c) i.e,1/9(21*9)

=189/9

=21

therefore a(the first no.) is 21

hope it helps

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Step-by-step explanation:

Answer 2

Answer: 21

Step-by-step explanation:

In the attachment