Chemistry, asked by kaviBoSAHAdvsv, 1 year ago

The +3 oxidation state of lanthanum(z=57),gadilinium(z=64)and lutecium(z=71) is especially stable , why?

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Answered by amruthadeshpande
2
The +3 oxidation state of lanthanum(z=57),gadilinium(z=64)and lutecium(z=71) is especially stable. This is because they have empty, half filled and completely filled 4f sub- shell respectively.

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