Question

The 300 N crate slides down the inclined curved path from A to B in the vertical plane as shown in the figure. If the crate has a velocity of 1.2 m/s down the inclined at point A and 8 m/s at B. Find the work done against friction during the motion.

Answer 1

hope it's give u a clue

Answer 2

Answer: 860 N m

Explanation:

From work energy theorem,

(Work done)P.E -Work done by frictional force = change in K.E

=> 300*6 - Wf = 1/2*(30)*(8²-1.2²) = 15*(62.56)

=> Wf = 1800 -938.4

=> wf = 860 N m (approx)