Question

the 31st term of the sequence 5; 11;17;23;29;35;41 is​

Answer 1

★ Given :-

• First term = a = 5
• Common difference = d = 11 - 5 = 6

★ To find :-

→ 31st term = a₃₁ = ?

★ Solution :-

A set of numbers is said to be in A.P or Arithmetic Progression if there is a constant Common difference between the terms.

For finding the nth term we use this formula:

aₙ = a + (n - 1)d

Where;

1. aₙ is the nth term
2. n is the number of terms

aₙ = a + (n - 1)d

⇒ a₃₁ = 5 + (31 - 1)6

⇒ a₃₁ = 5 + 30(6)

⇒ a₃₁ = 5 + 180

⇒ a₃₁ = 185

∴ The 31st term of the A.P is 185