Math, asked by gauri19more, 10 months ago

The 3D solid given below has edges of equal length of 16 cm. A rectangular hole of dimensions 4x3 cm and depth 2 cm is made in the centre of each face. Calculate the total surface are of the resulting solid in square cm.


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Answers

Answered by amitnrw
1

Given : A solid cube with edges of equal length of 16 cm.  A rectangular hole of dimensions 4x3 cm and depth 2 cm is made in the centre of each face.

To Find :  total surface are of the resulting solid in square cm

Solution:

Surface area of cube =6 x 16²  =  1536 cm²  

4x3 cm holes on each Face reduced  = 12 * 6  = 72 cm²

Hence Area = 1536 - 72 =  1464 cm²

Now surface area created because of depth  of  2 cm  

=  6  * ( 4 * 3  +  ( 4*2 + 3*2) * 2    )

= 6 ( 12 + 28)

= 240  cm²

Total Surface Area = 1464 + 240   = 1704 cm²  

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