the 3question answer
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hope this is enough to understand
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aathifa:
tqu so much
welcome :-)
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let thita be A
LHS
={( √1+cosA × √1+cosA ) + ( √1-cosA × √1-cosA )}/
√1-sin^2A
={ 1+cosA+1-cosA}÷sinA
=2/sinA
=2cosecA
=RHS
HENCE PROVED
LHS
={( √1+cosA × √1+cosA ) + ( √1-cosA × √1-cosA )}/
√1-sin^2A
={ 1+cosA+1-cosA}÷sinA
=2/sinA
=2cosecA
=RHS
HENCE PROVED
welcome
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