The 3rd and 6th term of an arithmetic sequence are 13 and 25 respectively. (a) What is its common difference? (b) What is its 15th term?
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Answered by
6
Answer:
Let first term be a and d be the common difference
3rd term =a+2d=13
6th term =a+5d=−5
3d=−5−13=−18
d=−6,a=25
11th term =a+10d=25−60=−35
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Answered by
1
Answer:
Let first term be a and d be the common difference
3rd term =a+2d=13
6th term=a+5d=-5
3d=-5-13--18
d=-6,a=25
11th term=a+10d=25-60=-35
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