the 3rd and 6th term of ap is 16and37
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Step-by-step explanation:
given
T3= a+2d
a+2d=16------(1)
T6= a+5d
a+5d=37--------(2)
subtract ( I) and (2)
a+2d-a-5d=16-37
-3d=-21
d=7
from( 1) a= 37-5×7= 37-35=2
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