Question

The 3rd and 6th terms of a Geometrical Progression are 48 and 14,2/9 respectively .Write down the first four terms of the Geometrical Progression

Answer 1

Step-by-step explanation:

In the GP

ar^2 = 50 …(1) and

ar^5 = -40 …(2)

Divide (2) by (1) to ger

r^3 = -40/50 = -(4/5) = -0.8, or r =(-0.8)^(1/3) = -0.928317766

The ninth term of the GP = ar^8 = ar^5*r^3 = -40(-0.8) = 32.