the 3rd term of an A.P. is 18 and 7 term is 30 . find 17th term
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ATQ,
a3=18
a+2d=18 ........ taking equation 1
a7=30
a+6d=30 ........... taking equation 2
solving 1 and 2 by elemination method we get
-4d= -12
d=3 ...... taking equation 3
putting 3 in 1
a=18-6= 12
a17 = a+16d
12+16(3)
12+48=60
a3=18
a+2d=18 ........ taking equation 1
a7=30
a+6d=30 ........... taking equation 2
solving 1 and 2 by elemination method we get
-4d= -12
d=3 ...... taking equation 3
putting 3 in 1
a=18-6= 12
a17 = a+16d
12+16(3)
12+48=60
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