the 3rd term of an AP is p and the fourth term is q. find the 10th term
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Hêyá ûr answèr îs hérē
= >3rd term=a+2d
=>4th term=a+3d
a/c to question,
a+2d=p--------------(1)
a+3d=q--------------(2)
on subtracting eq (2) from eq(1)
we get, -d=p-q
=>d=-(p-q)= -p+q✓✓
now, putting the value of d in eq.(1)
=>a+2d
=>a=2(-p+q)✓✓
now, we have a=2(-p-q) and d=-p+q
10th term = a+9d
putting the value of a and d in eq.
=>a+9d
=>2(-p+q)+9(-p+q)
therefore, 10th term ís 2(-p+q)+9(-p+q)
✌️✌️ Hópé ît helps ù✌️✌️
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