Question

The 3rd term of an arithmetic sequence is 43 and 6th term 76 write first 3 term and find the 10 th term


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Answer 1

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Answer 2

Answer:

Cd=76-43=33

6-3=3

33÷3=11

x1=43-22=21

x2=21+11=32

x3=43

x4=43+11=54

x5=54+11=65

SEQUENCE IS 21,32,43,54,65,76