The 3rd term of an arithmetic sequence is 43 and 6th term 76 write first 3 term and find the 10 th term
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Cd=76-43=33
6-3=3
33÷3=11
x1=43-22=21
x2=21+11=32
x3=43
x4=43+11=54
x5=54+11=65
SEQUENCE IS 21,32,43,54,65,76
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