Question

The 3rd term of an arithmetic sequence is 43 and 6th term 76 write first 3 term and find the 10 th term
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Answer 1

Answer:

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Answer 2

Answer:

120

Step-by-step explanation: mark brainleist

n3 = a +2d = 43

n6 = a + 5d = 76

Subtract

3d = 33

⇒d = 11

a + 5d = 76

a + 55 = 76

⇒a = 21

n10 = a + 9d = 21 + 99 = 120