The 4 angles of a quadrilateral form an AP. if the sum of first 3 angles are 60 more than the 4th angle,find all the angles
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Answer:
fourth angle = 60°
sum of first three angles = 210°
Step-by-step explanation:
let abcd is a quadrilateral
forth angle = x
sum of first three angles = x+60
the sum of angles of quadrilateral = 360°
∠a+∠b+∠c+∠d =360°
x+60 + x =360°
2x+60=360°
2x = 360°-60°
2x =300°
⇒x=150°
fourth angle = x= 150°
sum of first three angles = x+60°
= 150°+60° =210°
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