Question

The 4 kg head of a sledge hammer is moving at 6 m/s when it strikes a spike dividing it into a log,
the duration of the impact is 2 ms. find the time average of the impact force.
solve this and if you play pubg lite send a request to my id EpicWarrioR
rank crown 1
​

Answer 1

Explanation:

hope it helps you please mark as brainliest please

Answer 2

Mass of the hammer, m = 4 kg

Velocity when it strikes, v = 6 m/s

So, momentum before striking = mv = 24 Ns

After striking it comes to rest in 2 ms = 2 × 10-3 s or 0.002 s

Momentum after this time = 0

So, change in momentum, |Δp| = |0 - 24| = 24 Ns

Average force of impact is, F = |Δp|/Δt = 24/0.002

=> F = 12000 N

Hope this helps you If so please mark it as Brainliest Answer!! ☺️ ☺️

By soniabikash