The 4th and 7th term of gp is 1/27and 1/729.find the sum of n terms of gp
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Answered by
31
Hi , there !!!
4th term of GP is = ar³ = 1/ 27
7th term of GP is ar^6= 1/729
dividing both
we get
r³ = 27
r = 3
ar³ = 1/ 27
a =1/ 81
first nth term will be
ar ^ n -1
=> 1/ 81 × 3 ^ n-1
=> 1 / 27 ^ n-1
hope it help you
thanks !!
Ranjankumar
4th term of GP is = ar³ = 1/ 27
7th term of GP is ar^6= 1/729
dividing both
we get
r³ = 27
r = 3
ar³ = 1/ 27
a =1/ 81
first nth term will be
ar ^ n -1
=> 1/ 81 × 3 ^ n-1
=> 1 / 27 ^ n-1
hope it help you
thanks !!
Ranjankumar
Answered by
22
Hi , there !!!
4th term of GP is = ar³ = 1/ 27
7th term of GP is ar^6= 1/729
dividing both
we get
r³ = 27
r = 3
ar³ = 1/ 27
a =1/ 81
first nth term will be
ar ^ n -1
=> 1/ 81 × 3 ^ n-1
=> 1 / 27 ^ n-1
hope it help you
thanks !!
Ranjankumar
4th term of GP is = ar³ = 1/ 27
7th term of GP is ar^6= 1/729
dividing both
we get
r³ = 27
r = 3
ar³ = 1/ 27
a =1/ 81
first nth term will be
ar ^ n -1
=> 1/ 81 × 3 ^ n-1
=> 1 / 27 ^ n-1
hope it help you
thanks !!
Ranjankumar
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