Question

the 4th and the last terms of an A.P are 11 and 89 respectively . if therefore 30 terms in the A.P find the A.P and its 23rd terms.​

Answer 1

Step-by-step explanation:

we can write 4th term of ap as a+3d=11

and same as for 30th term of ap as a+29d=89

we get 2 equation.

by solving we get find the value of a and d

then we have to find 23rd term

we can write 23rd term as a+22d

put value of a and d in a+22d

you get answer