the 4th question along with the sum. pls I will mark u as brainliest
Answers
Answer:
Distance travelled in 5 seconds,
s=ut+1/2at²
s=1/2gt²
=1/2×9.8*(5)²
=122.5 m
Distance travelled in 5th second,
Sn=u+a/2(2n-1)
Sn=g/2(2n-1)
S5=9.8/2(2×5-1)
=4.9(10-1)
=4.9×9
∴S5=44.1 m
∴Ratio=122.5/44.1=2.77
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